"Ballpark Factor" Revisited
A lot has been made recently about the "Ballpark Factor" of U.S. Cellular Field in Chicago. Specifically, it is now regarded by most as the best HR park in the AL. After considering it, I challenge this assumption, and in fact the whole way "Ballpark Factor" is computed.
For "Ballpark Factor", both The Bill James Handbook and baseballhq.com use the same concept - take the homers hit in a park (home and opposition) and divide it by the homers hit on the road (home and opp). Actually, the home run rates are divided, so taking the 2004 A's as an example:
Home: 154/4992 (A's 84, opp 70).
Road: 153/5082 (A's 82, opp 71).
==> ballpark HR factor of 102, or +2%.
If I go to baseballhq.com, I can see that for the period 2003-2005, US Cellular is a whopping +31%+37% (lefty/righty) for HR. So, in theory games held at The Cell should produce about 1/3 more HR than games held at a "neutral park". Therein lies the rub. The Chicago White Sox play a disproportianately high percenage of their games in VERY POOR home run parks.
Cleveland: -21-28 (L/R HR% 03-05)
Kansas City: -27/26
Detroit: 0/-15
Minnesota: 0/0 (was negative both sides 02-04)
<information taken from baseballhq.com>
In fact... if you look at White Sox games in these ballparks, there were approximately 1.5 HR hit in each game. Here are the top HR/G for various parks the Sox played in (again, both home and opp HRs are counted):
Fenway: 4.7 HR/9 ip
Ameriquest: 3.9
Rogers Centre: 3.7
Wrigley Field: 2.8
U.S. Cellular: 2.6
In fact, if you give each road ballpark a weight of "1" (instead of giving - in essence - each ballpark a weight of the number of innings played there), the Sox road games averaged 2.1 HR/9 ip.
So, if you don't give extra weight to the parks in the Sox division, The Cell comes up with a BF of 121 in 2005 (2.6 HR/9ip home divided by 2.1 HR/9ip road). This is still high - perhaps higher than any other park using this method, I haven't applied the same calculations to Texas or Toronto. But it's a lot different than the 131/137 BF as published.
Take it for what it's worth. Javier Vazquez will allow a lot of homers in US Cellular. I'm just saying it's likely not as bad as it may appear to be at first. I think the above method is more legitimate for computing BF, and I think that if done for San Diego, a large change will be noted also.
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Kaufman, Context Chnages
by FI on Dec 22, 2005 7:24 AM EST reply actions
im a bit confuzzled
at bats
ive never really thought about this before
Am I being dumb and missing something, or do I have a point here?
I agree
My point is only regarding the weighting of every AB the same, when teams play an unequal number of games (hence AB) at various road parks. So, the average Sox (or Padres) road game will be a lot different than the average Rangers (or Rockies) road game. It may be accurate to say that The Cell increased power output by 35% over their road games. But to say that Javier Vazquez will neccessarily allow more HR playing for the White Sox - just because the CHA metric is higher than the ARI metric - isn't accurate. Part of the "package" of being a White Sock is getting to play road games at Kauffman, Metrodome, Comerica, and Jacobs, and those games will knock some HR's off your total, while at the same time increasing the BF metric for the Sox.
Context
by Buzzards Bay on Dec 25, 2005 7:29 PM EST reply actions
I agree again...
The other point I'm making is that to neutralize the contextual influences somewhat, you can take the HR% in home games and compare this not to the composite HR% in road games, but rather to the average of each road stadium's games. So, if HR(x) is the Home Run percentage at venue x, I'm saying that
HR(home)*13/(HR(1)+HR(2)+ ... + HR(13))
is a more-accurate metric than taking
HR(home)/HR(road),
where HR(road) is the rate computed by using the sum of all homers hit and allowed in road games.
Think about an analogy...
Assume: 75% of league plate appearances are against RHP. Analyzing the BA differences between two full-time batters...
Over 200 AB, Batter A has 100 AB against LHP and 100 against RHP. He hits .500 against LHP (50 hits), and .200 against RHP (20 hits). That's 70 H/200 AB => .350
Batter B has 50 AB against LHP and 150 AB against RHP. He hits .300 against everyone (60 hits) => .300
If these are their true levels of ability, who will hit better over the next 200 AB? If Batter A sees 75% RHP, he will pick up 25 (.500 x 50) plus 30 (.200 x 150) hits, for 55 total (.275). Batter B will again log 60 hits (.300).
Ballpark
by Buzzards Bay on Jan 6, 2006 8:20 PM EST reply actions

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